(3-x^2)-(2x^2-5x^4)=0

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Solution for (3-x^2)-(2x^2-5x^4)=0 equation:


Simplifying
(3 + -1x2) + -1(2x2 + -5x4) = 0

Remove parenthesis around (3 + -1x2)
3 + -1x2 + -1(2x2 + -5x4) = 0
3 + -1x2 + (2x2 * -1 + -5x4 * -1) = 0
3 + -1x2 + (-2x2 + 5x4) = 0

Combine like terms: -1x2 + -2x2 = -3x2
3 + -3x2 + 5x4 = 0

Solving
3 + -3x2 + 5x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.6 + -0.6x2 + x4 = 0

Move the constant term to the right:

Add '-0.6' to each side of the equation.
0.6 + -0.6x2 + -0.6 + x4 = 0 + -0.6

Reorder the terms:
0.6 + -0.6 + -0.6x2 + x4 = 0 + -0.6

Combine like terms: 0.6 + -0.6 = 0.0
0.0 + -0.6x2 + x4 = 0 + -0.6
-0.6x2 + x4 = 0 + -0.6

Combine like terms: 0 + -0.6 = -0.6
-0.6x2 + x4 = -0.6

The x term is -0.6x2.  Take half its coefficient (-0.3).
Square it (0.09) and add it to both sides.

Add '0.09' to each side of the equation.
-0.6x2 + 0.09 + x4 = -0.6 + 0.09

Reorder the terms:
0.09 + -0.6x2 + x4 = -0.6 + 0.09

Combine like terms: -0.6 + 0.09 = -0.51
0.09 + -0.6x2 + x4 = -0.51

Factor a perfect square on the left side:
(x2 + -0.3)(x2 + -0.3) = -0.51

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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